Projectile Motion
A wheeled car with a spring-loaded cannon fires a metal ball vertically. If the vertical initial speed of the ball is 50 m/s as the cannon moves horizontally at a speed of 0.75 m/s, a) how far from the launch point does the ball fall back into the cannon, and b) what would happen if the cannon were accelerating?
The ball will land inside the cannon 1.226 m from where it left. Y=5.0 (.5)+(.5)(9.8) this represents the vertical change that will occur when a metal ball is shot out of a cannon. the time was found by using the velocity equation because we are given both the final and initial velocities.
0=5.0+(-9.8)t this is that equation which gives the time which comes out to be 0.51 s. Now for question b if the cannon were accelerating the ball would miss because after the ball is shot the ball's acceleration becomes gravity in the downward direction.
0=5.0+(-9.8)t this is that equation which gives the time which comes out to be 0.51 s. Now for question b if the cannon were accelerating the ball would miss because after the ball is shot the ball's acceleration becomes gravity in the downward direction.